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"Make a sulution of water and zinc sulfate heptahydrate that when added to beer wort at a rate of 1 ml/l yields 0.1 ppm elemental zinc per liter"
To prepare a zinc sulfate heptahydrate solution that, when dosed at 1 mL per liter of beer wort, yields 0.1 ppm (mg/L) elemental zinc, follow these steps:
Calculation of Required Solution Concentration
1. Determine the desired zinc addition per liter:
Target: 0.1 mg elemental zinc per liter of wort.
2. Amount of zinc needed per 1 mL of solution:
Since you will add 1 mL solution per 1 L wort, the solution must contain 0.1 mg zinc per mL.
3. Calculate how much zinc sulfate heptahydrate (ZnSO₄·7H₂O) to dissolve:
Molar mass of ZnSO₄·7H₂O ≈ 287.54 g/mol.
Each mole contains 1 mole of Zn (65.38 g/mol).
Fraction of zinc by mass: 65.38 / 287.54 ≈ 0.227.
4. Find the amount of ZnSO₄·7H₂O needed for 0.1 mg Zn:
0.1 mg Zn × (1 g ZnSO₄·7H₂O / 0.227 g Zn) ≈ 0.44 mg ZnSO₄·7H₂O per mL.
5. Scale up for practical solution preparation (e.g., 1 L):
1 L = 1000 mL → 0.44 mg × 1000 = 440 mg ZnSO₄·7H₂O per liter of solution.
Preparation Steps
Accurately weigh 440 mg of zinc sulfate heptahydrate (ZnSO₄·7H₂O).
Dissolve the 440 mg in distilled or deionized water.
Dilute to a final volume of 1 liter.
Mix thoroughly.
Usage
Add 1 mL of this solution per 1 L of wort to achieve 0.1 ppm elemental zinc.
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